-1,5x^2-72x+2500=0

Solution for -1,5x^2-72x+2500=0 equation:

-1.5x^2-72x+2500=0

a = -1.5; b = -72; c = +2500;
Δ = b2-4ac
Δ = -722-4·(-1.5)·2500
Δ = 20184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20184}=\sqrt{3364*6}=\sqrt{3364}*\sqrt{6}=58\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-58\sqrt{6}}{2*-1.5}=\frac{72-58\sqrt{6}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+58\sqrt{6}}{2*-1.5}=\frac{72+58\sqrt{6}}{-3}
$